Solve the following pair of linear equations | vedclass

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(B) Given equations are:$1) \, 2x - 3y = 5$$2) \, 4x - 6y = -13$Comparing these with the standard form $a_1x + b_1y + c_1 = 0$ and $a_2x + b_2y + c_2

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$	ext{No solution } (\varnothing)$

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(B) Given equations are:$1) \, 2x - 3y = 5$$2) \, 4x - 6y = -13$Comparing these with the standard form $a_1x + b_1y + c_1 = 0$ and $a_2x + b_2y + c_2 = 0$:$a_1 = 2, b_1 = -3, c_1 = -5$$a_2 = 4, b_2 = -6, c_2 = 13$Calculating the ratios:$\frac{a_1}{a_2} = \frac{2}{4} = \frac{1}{2}$$\frac{b_1}{b_2} = \frac{-3}{-6} = \frac{1}{2}$$\frac{c_1}{c_2} = \frac{-5}{13}$Since $\frac{a_1}{a_2} = \frac{b_1}{b_2} 
eq \frac{c_1}{c_2}$,the lines represented by these equations are parallel to each other.Parallel lines do not intersect at any point,which means the system of equations has no solution $(\varnothing)$.

Solve the following pair of linear equations in two variables using a graph: $2x - 3y = 5$ and $4x - 6y = -13$.

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